Gujarati
Hindi
1. Electric Charges and Fields
normal

The conducting spherical shells shown in the figure are connected by a conductor. The capacitance of the system is

A

$4\pi {\varepsilon _0}\,\frac{{ab}}{{b - a}}$

B

$4\pi {\varepsilon _0}\,a$

C

$4\pi {\varepsilon _0}\,b$

D

$4\pi {\varepsilon _0}\,\frac{{{a^2}}}{{b - a}}$

Solution

Hence, the capacitance of the system is the capacitance due to outer sphere of radius $\mathrm{b}.$

$\therefore \quad \mathrm{C}=4 \pi \varepsilon_{0} \mathrm{b}$

Standard 12
Physics

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