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1. Electric Charges and Fields
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The conducting spherical shells shown in the figure are connected by a conductor. The capacitance of the system is

A
$4\pi {\varepsilon _0}\,\frac{{ab}}{{b - a}}$
B
$4\pi {\varepsilon _0}\,a$
C
$4\pi {\varepsilon _0}\,b$
D
$4\pi {\varepsilon _0}\,\frac{{{a^2}}}{{b - a}}$
Solution
Hence, the capacitance of the system is the capacitance due to outer sphere of radius $\mathrm{b}.$
$\therefore \quad \mathrm{C}=4 \pi \varepsilon_{0} \mathrm{b}$
Standard 12
Physics
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